Base | Representation |
---|---|
bin | 110011100111111101… |
… | …101101001101010001 |
3 | 12022002002210211112201 |
4 | 303213331231031101 |
5 | 1402010404223101 |
6 | 41244221323201 |
7 | 4001432310052 |
oct | 634775551521 |
9 | 168062724481 |
10 | 55431320401 |
11 | 215655984a6 |
12 | a8aba06501 |
13 | 52c5087b92 |
14 | 297bbca729 |
15 | 16965e9e01 |
hex | ce7f6d351 |
55431320401 has 2 divisors, whose sum is σ = 55431320402. Its totient is φ = 55431320400.
The previous prime is 55431320393. The next prime is 55431320471. The reversal of 55431320401 is 10402313455.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 46287371025 + 9143949376 = 215145^2 + 95624^2 .
It is a cyclic number.
It is not a de Polignac number, because 55431320401 - 23 = 55431320393 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 55431320401.
It is not a weakly prime, because it can be changed into another prime (55431320471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27715660200 + 27715660201.
It is an arithmetic number, because the mean of its divisors is an integer number (27715660201).
Almost surely, 255431320401 is an apocalyptic number.
It is an amenable number.
55431320401 is a deficient number, since it is larger than the sum of its proper divisors (1).
55431320401 is an equidigital number, since it uses as much as digits as its factorization.
55431320401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 55431320401 its reverse (10402313455), we get a palindrome (65833633856).
The spelling of 55431320401 in words is "fifty-five billion, four hundred thirty-one million, three hundred twenty thousand, four hundred one".
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