Base | Representation |
---|---|
bin | 110011100111111110… |
… | …000000101001001001 |
3 | 12022002002221212202011 |
4 | 303213332000221021 |
5 | 1402010414300014 |
6 | 41244223135521 |
7 | 4001433061126 |
oct | 634776005111 |
9 | 168062855664 |
10 | 55431400009 |
11 | 21565642297 |
12 | a8aba445a1 |
13 | 52c50b519b |
14 | 297bc0b74d |
15 | 16966137c4 |
hex | ce7f80a49 |
55431400009 has 2 divisors, whose sum is σ = 55431400010. Its totient is φ = 55431400008.
The previous prime is 55431400001. The next prime is 55431400021. The reversal of 55431400009 is 90000413455.
55431400009 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 55038567609 + 392832400 = 234603^2 + 19820^2 .
It is a cyclic number.
It is not a de Polignac number, because 55431400009 - 23 = 55431400001 is a prime.
It is not a weakly prime, because it can be changed into another prime (55431400001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27715700004 + 27715700005.
It is an arithmetic number, because the mean of its divisors is an integer number (27715700005).
Almost surely, 255431400009 is an apocalyptic number.
It is an amenable number.
55431400009 is a deficient number, since it is larger than the sum of its proper divisors (1).
55431400009 is an equidigital number, since it uses as much as digits as its factorization.
55431400009 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 31.
The spelling of 55431400009 in words is "fifty-five billion, four hundred thirty-one million, four hundred thousand, nine".
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