55433130041 has 8 divisors (see below), whose sum is σ = 55970537544. Its totient is φ = 54898216960.

The previous prime is 55433130007. The next prime is 55433130061. The reversal of 55433130041 is 14003133455.

It can be written as a sum of positive squares in 4 ways, for example, as 49552540816 + 5880589225 = 222604^2 + 76685^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-55433130041 is a prime.

It is a super-2 number, since 2×55433130041² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 55433129986 and 55433130013.

It is not an unprimeable number, because it can be changed into a prime (55433130061) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 578930 + ... + 667851.

It is an arithmetic number, because the mean of its divisors is an integer number (6996317193).

Almost surely, 2^55433130041 is an apocalyptic number.

It is an amenable number.

55433130041 is a deficient number, since it is larger than the sum of its proper divisors (537407503).

55433130041 is a wasteful number, since it uses less digits than its factorization.

55433130041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1247211.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 55433130041 its reverse (14003133455), we get a palindrome (69436263496).

The spelling of 55433130041 in words is "fifty-five billion, four hundred thirty-three million, one hundred thirty thousand, forty-one".