55433535433 has 2 divisors, whose sum is σ = 55433535434. Its totient is φ = 55433535432.

The previous prime is 55433535419. The next prime is 55433535461. The reversal of 55433535433 is 33453533455.

55433535433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 42688931769 + 12744603664 = 206613^2 + 112892^2 .

It is a cyclic number.

It is not a de Polignac number, because 55433535433 - 2⁹ = 55433534921 is a prime.

It is a super-3 number, since 3×55433535433³ (a number of 33 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 55433535433.

It is not a weakly prime, because it can be changed into another prime (55433535413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27716767716 + 27716767717.

It is an arithmetic number, because the mean of its divisors is an integer number (27716767717).

Almost surely, 2^55433535433 is an apocalyptic number.

It is an amenable number.

55433535433 is a deficient number, since it is larger than the sum of its proper divisors (1).

55433535433 is an equidigital number, since it uses as much as digits as its factorization.

55433535433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2430000, while the sum is 43.

The spelling of 55433535433 in words is "fifty-five billion, four hundred thirty-three million, five hundred thirty-five thousand, four hundred thirty-three".