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554341223313401 is a prime number
BaseRepresentation
bin111111000001010111001111…
…1101100110010111111111001
32200200202111120222021221020212
41332002232133230302333321
51040124311311132012101
65242552501541000505
7224522555166042626
oct17602563754627771
92620674528257225
10554341223313401
111506a2879a07277
125220b0620b3135
131aa411cb35b314
149ac6388d5134d
154414a49ca21bb
hex1f82b9fb32ff9

554341223313401 has 2 divisors, whose sum is σ = 554341223313402. Its totient is φ = 554341223313400.

The previous prime is 554341223313347. The next prime is 554341223313467. The reversal of 554341223313401 is 104313322143455.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 494174456101225 + 60166767212176 = 22230035^2 + 7756724^2 .

It is a cyclic number.

It is not a de Polignac number, because 554341223313401 - 230 = 554340149571577 is a prime.

It is not a weakly prime, because it can be changed into another prime (554341223315401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277170611656700 + 277170611656701.

It is an arithmetic number, because the mean of its divisors is an integer number (277170611656701).

Almost surely, 2554341223313401 is an apocalyptic number.

It is an amenable number.

554341223313401 is a deficient number, since it is larger than the sum of its proper divisors (1).

554341223313401 is an equidigital number, since it uses as much as digits as its factorization.

554341223313401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 518400, while the sum is 41.

Adding to 554341223313401 its reverse (104313322143455), we get a palindrome (658654545456856).

The spelling of 554341223313401 in words is "five hundred fifty-four trillion, three hundred forty-one billion, two hundred twenty-three million, three hundred thirteen thousand, four hundred one".