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55434401401 is a prime number
BaseRepresentation
bin110011101000001001…
…011101011001111001
312022002022121100212211
4303220021131121321
51402012201321101
641244411335121
74001500431421
oct635011353171
9168068540784
1055434401401
1121567302285
12a8b0a514a1
1352c58c6362
14297c38d481
151696a07c51
hexce825d679

55434401401 has 2 divisors, whose sum is σ = 55434401402. Its totient is φ = 55434401400.

The previous prime is 55434401389. The next prime is 55434401447. The reversal of 55434401401 is 10410443455.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 54587649600 + 846751801 = 233640^2 + 29099^2 .

It is a cyclic number.

It is not a de Polignac number, because 55434401401 - 235 = 21074663033 is a prime.

It is not a weakly prime, because it can be changed into another prime (55434401471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27717200700 + 27717200701.

It is an arithmetic number, because the mean of its divisors is an integer number (27717200701).

Almost surely, 255434401401 is an apocalyptic number.

It is an amenable number.

55434401401 is a deficient number, since it is larger than the sum of its proper divisors (1).

55434401401 is an equidigital number, since it uses as much as digits as its factorization.

55434401401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 55434401401 its reverse (10410443455), we get a palindrome (65844844856).

The spelling of 55434401401 in words is "fifty-five billion, four hundred thirty-four million, four hundred one thousand, four hundred one".