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55435401011 = 151367121861
BaseRepresentation
bin110011101000001101…
…010001011100110011
312022002101111011002102
4303220031101130303
51402012430313021
641244445011015
74001512063634
oct635015213463
9168071434072
1055435401011
1121567925301
12a8b1253a6b
1352c5b86343
14297c56d88b
151696b5400b
hexce8351733

55435401011 has 4 divisors (see below), whose sum is σ = 55802523024. Its totient is φ = 55068279000.

The previous prime is 55435400983. The next prime is 55435401029. The reversal of 55435401011 is 11010453455.

55435401011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55435401011 - 234 = 38255531827 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55435401611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183560780 + ... + 183561081.

It is an arithmetic number, because the mean of its divisors is an integer number (13950630756).

Almost surely, 255435401011 is an apocalyptic number.

55435401011 is a deficient number, since it is larger than the sum of its proper divisors (367122013).

55435401011 is a wasteful number, since it uses less digits than its factorization.

55435401011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 367122012.

The product of its (nonzero) digits is 6000, while the sum is 29.

Adding to 55435401011 its reverse (11010453455), we get a palindrome (66445854466).

The spelling of 55435401011 in words is "fifty-five billion, four hundred thirty-five million, four hundred one thousand, eleven".

Divisors: 1 151 367121861 55435401011