Base | Representation |
---|---|
bin | 101000010110010101001… |
… | …1100111100011010001001 |
3 | 201122010221110211220011201 |
4 | 1100230222130330122021 |
5 | 1211324203320302143 |
6 | 15443324024224201 |
7 | 1111436013556642 |
oct | 120545234743211 |
9 | 21563843756151 |
10 | 5545515009673 |
11 | 1848926719431 |
12 | 75691190b061 |
13 | 312c2aa32112 |
14 | 1525937ba6c9 |
15 | 993b90c364d |
hex | 50b2a73c689 |
5545515009673 has 2 divisors, whose sum is σ = 5545515009674. Its totient is φ = 5545515009672.
The previous prime is 5545515009583. The next prime is 5545515009707. The reversal of 5545515009673 is 3769005155455.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2865392406009 + 2680122603664 = 1692747^2 + 1637108^2 .
It is a cyclic number.
It is not a de Polignac number, because 5545515009673 - 29 = 5545515009161 is a prime.
It is not a weakly prime, because it can be changed into another prime (5545515409673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2772757504836 + 2772757504837.
It is an arithmetic number, because the mean of its divisors is an integer number (2772757504837).
Almost surely, 25545515009673 is an apocalyptic number.
It is an amenable number.
5545515009673 is a deficient number, since it is larger than the sum of its proper divisors (1).
5545515009673 is an equidigital number, since it uses as much as digits as its factorization.
5545515009673 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14175000, while the sum is 55.
The spelling of 5545515009673 in words is "five trillion, five hundred forty-five billion, five hundred fifteen million, nine thousand, six hundred seventy-three".
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