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5547335614081 is a prime number
BaseRepresentation
bin101000010111001011011…
…1101111111111010000001
3201122022122100122011220121
41100232112331333322001
51211341420404122311
615444224422140241
71111532101501342
oct120562675777201
921568570564817
105547335614081
111849680376478
1275713b581681
1331315ac87731
141526c74d80c9
1599473d4bb71
hex50b96f7fe81

5547335614081 has 2 divisors, whose sum is σ = 5547335614082. Its totient is φ = 5547335614080.

The previous prime is 5547335614031. The next prime is 5547335614111. The reversal of 5547335614081 is 1804165337455.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5305582458225 + 241753155856 = 2303385^2 + 491684^2 .

It is a cyclic number.

It is not a de Polignac number, because 5547335614081 - 217 = 5547335483009 is a prime.

It is a super-2 number, since 2×55473356140812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5547335614031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2773667807040 + 2773667807041.

It is an arithmetic number, because the mean of its divisors is an integer number (2773667807041).

Almost surely, 25547335614081 is an apocalyptic number.

It is an amenable number.

5547335614081 is a deficient number, since it is larger than the sum of its proper divisors (1).

5547335614081 is an equidigital number, since it uses as much as digits as its factorization.

5547335614081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048000, while the sum is 52.

The spelling of 5547335614081 in words is "five trillion, five hundred forty-seven billion, three hundred thirty-five million, six hundred fourteen thousand, eighty-one".