Base | Representation |
---|---|
bin | 110011101011011111… |
… | …011000001001101001 |
3 | 12022020020010101110201 |
4 | 303223133120021221 |
5 | 1402121030304242 |
6 | 41254133312201 |
7 | 4003051200163 |
oct | 635337301151 |
9 | 168206111421 |
10 | 55490478697 |
11 | 21595a23a55 |
12 | a907795661 |
13 | 53043cb9a4 |
14 | 29859c9933 |
15 | 169b8d34b7 |
hex | ceb7d8269 |
55490478697 has 4 divisors (see below), whose sum is σ = 55497525840. Its totient is φ = 55483431556.
The previous prime is 55490478691. The next prime is 55490478731. The reversal of 55490478697 is 79687409455.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55490478697 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55490478691) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3511747 + ... + 3527512.
It is an arithmetic number, because the mean of its divisors is an integer number (13874381460).
Almost surely, 255490478697 is an apocalyptic number.
It is an amenable number.
55490478697 is a deficient number, since it is larger than the sum of its proper divisors (7047143).
55490478697 is an equidigital number, since it uses as much as digits as its factorization.
55490478697 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7047142.
The product of its (nonzero) digits is 76204800, while the sum is 64.
The spelling of 55490478697 in words is "fifty-five billion, four hundred ninety million, four hundred seventy-eight thousand, six hundred ninety-seven".
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