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5550032510137 is a prime number
BaseRepresentation
bin101000011000011011110…
…1101110101110010111001
3201122120121022022200210201
41100300313231311302321
51211412431310311022
615445352202042201
71111655656646143
oct120606755656271
921576538280721
105550032510137
11184a834732395
127577727a9361
1331349a92540b
141528a175dc93
15995809bc127
hex50c37b75cb9

5550032510137 has 2 divisors, whose sum is σ = 5550032510138. Its totient is φ = 5550032510136.

The previous prime is 5550032510101. The next prime is 5550032510179. The reversal of 5550032510137 is 7310152300555.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4913067303936 + 636965206201 = 2216544^2 + 798101^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5550032510137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5550032510096 and 5550032510105.

It is not a weakly prime, because it can be changed into another prime (5550032510837) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2775016255068 + 2775016255069.

It is an arithmetic number, because the mean of its divisors is an integer number (2775016255069).

Almost surely, 25550032510137 is an apocalyptic number.

It is an amenable number.

5550032510137 is a deficient number, since it is larger than the sum of its proper divisors (1).

5550032510137 is an equidigital number, since it uses as much as digits as its factorization.

5550032510137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 78750, while the sum is 37.

The spelling of 5550032510137 in words is "five trillion, five hundred fifty billion, thirty-two million, five hundred ten thousand, one hundred thirty-seven".