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5550132541042 = 231443202072837
BaseRepresentation
bin101000011000011110110…
…1011011011011001110010
3201122120212021112210102001
41100300331223123121302
51211413132412303132
615445410134044214
71111661313130345
oct120607553333162
921576767483361
105550132541042
11184a886145061
127577a01a966a
133134b5579cbb
141528b0b5c45c
159958967ace7
hex50c3dadb672

5550132541042 has 16 divisors (see below), whose sum is σ = 8613152646912. Its totient is φ = 2679485805360.

The previous prime is 5550132541033. The next prime is 5550132541069. The reversal of 5550132541042 is 2401452310555.

It is a super-3 number, since 3×55501325410423 (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5550132540992 and 5550132541010.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 101008953 + ... + 101063884.

It is an arithmetic number, because the mean of its divisors is an integer number (538322040432).

Almost surely, 25550132541042 is an apocalyptic number.

5550132541042 is a deficient number, since it is larger than the sum of its proper divisors (3063020105870).

5550132541042 is a wasteful number, since it uses less digits than its factorization.

5550132541042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 202073313.

The product of its (nonzero) digits is 120000, while the sum is 37.

Adding to 5550132541042 its reverse (2401452310555), we get a palindrome (7951584851597).

The spelling of 5550132541042 in words is "five trillion, five hundred fifty billion, one hundred thirty-two million, five hundred forty-one thousand, forty-two".

Divisors: 1 2 31 62 443 886 13733 27466 202072837 404145674 6264257947 12528515894 89518266791 179036533582 2775066270521 5550132541042