Base | Representation |
---|---|
bin | 11001001111011011000011… |
… | …11010010101110101101011 |
3 | 21021112021102002012121122221 |
4 | 30213231201322111311223 |
5 | 24233400233243044323 |
6 | 314014513233254511 |
7 | 14456066105256163 |
oct | 1447554172256553 |
9 | 237467362177587 |
10 | 55505505049963 |
11 | 1675a830636611 |
12 | 6285409404437 |
13 | 24c81ba2c6407 |
14 | d9c6a33835a3 |
15 | 663c5b43055d |
hex | 327b61e95d6b |
55505505049963 has 2 divisors, whose sum is σ = 55505505049964. Its totient is φ = 55505505049962.
The previous prime is 55505505049937. The next prime is 55505505050081. The reversal of 55505505049963 is 36994050550555.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55505505049963 - 213 = 55505505041771 is a prime.
It is a super-2 number, since 2×555055050499632 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (55505505046963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27752752524981 + 27752752524982.
It is an arithmetic number, because the mean of its divisors is an integer number (27752752524982).
Almost surely, 255505505049963 is an apocalyptic number.
55505505049963 is a deficient number, since it is larger than the sum of its proper divisors (1).
55505505049963 is an equidigital number, since it uses as much as digits as its factorization.
55505505049963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 91125000, while the sum is 61.
The spelling of 55505505049963 in words is "fifty-five trillion, five hundred five billion, five hundred five million, forty-nine thousand, nine hundred sixty-three".
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