Base | Representation |
---|---|
bin | 11001001111101111100011… |
… | …10111100010111110101011 |
3 | 21021120022211001021200201021 |
4 | 30213313301313202332223 |
5 | 24234040303100433201 |
6 | 314023533243233311 |
7 | 14456635606251256 |
oct | 1447676167427653 |
9 | 237508731250637 |
10 | 55516510171051 |
11 | 16764468751a06 |
12 | 628757ab18837 |
13 | 24c92522c4997 |
14 | d9d028bc809d |
15 | 6641a2681ea1 |
hex | 327df1de2fab |
55516510171051 has 2 divisors, whose sum is σ = 55516510171052. Its totient is φ = 55516510171050.
The previous prime is 55516510170997. The next prime is 55516510171103. The reversal of 55516510171051 is 15017101561555.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 55516510171051 - 217 = 55516510039979 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 55516510170989 and 55516510171007.
It is not a weakly prime, because it can be changed into another prime (55516510171651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27758255085525 + 27758255085526.
It is an arithmetic number, because the mean of its divisors is an integer number (27758255085526).
Almost surely, 255516510171051 is an apocalyptic number.
55516510171051 is a deficient number, since it is larger than the sum of its proper divisors (1).
55516510171051 is an equidigital number, since it uses as much as digits as its factorization.
55516510171051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 131250, while the sum is 43.
The spelling of 55516510171051 in words is "fifty-five trillion, five hundred sixteen billion, five hundred ten million, one hundred seventy-one thousand, fifty-one".
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