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555660000000097 is a prime number
BaseRepresentation
bin111111001010111101010110…
…0111010100111100001100001
32200212102120120210021220100121
41332111322230322213201201
51040312413140000000342
65245442402514120241
7225020052540654166
oct17625725472474141
92625376523256317
10555660000000097
1115106109aa79053
12523a2769880081
131ab08689565655
149b3013214406d
154438ed2350067
hex1f95eacea7861

555660000000097 has 2 divisors, whose sum is σ = 555660000000098. Its totient is φ = 555660000000096.

The previous prime is 555659999999987. The next prime is 555660000000107. The reversal of 555660000000097 is 790000000066555.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 370426838418576 + 185233161581521 = 19246476^2 + 13610039^2 .

It is a cyclic number.

It is not a de Polignac number, because 555660000000097 - 239 = 555110244186209 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 555659999999990 and 555660000000062.

It is not a weakly prime, because it can be changed into another prime (555660000000197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277830000000048 + 277830000000049.

It is an arithmetic number, because the mean of its divisors is an integer number (277830000000049).

Almost surely, 2555660000000097 is an apocalyptic number.

It is an amenable number.

555660000000097 is a deficient number, since it is larger than the sum of its proper divisors (1).

555660000000097 is an equidigital number, since it uses as much as digits as its factorization.

555660000000097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 283500, while the sum is 43.

The spelling of 555660000000097 in words is "five hundred fifty-five trillion, six hundred sixty billion, ninety-seven", and thus it is an aban number.