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55601214153 = 318533738051
BaseRepresentation
bin110011110010000101…
…110011001011001001
312022111221111022221220
4303302011303023021
51402332402323103
641313130552253
74005564344112
oct636205631311
9168457438856
1055601214153
1121642488161
12a938898689
135321330a24
1429965b3209
1516a64a8c53
hexcf21732c9

55601214153 has 4 divisors (see below), whose sum is σ = 74134952208. Its totient is φ = 37067476100.

The previous prime is 55601214059. The next prime is 55601214181. The reversal of 55601214153 is 35141210655.

55601214153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55601214153 - 217 = 55601083081 is a prime.

It is not an unprimeable number, because it can be changed into a prime (55601214653) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9266869023 + ... + 9266869028.

It is an arithmetic number, because the mean of its divisors is an integer number (18533738052).

Almost surely, 255601214153 is an apocalyptic number.

It is an amenable number.

55601214153 is a deficient number, since it is larger than the sum of its proper divisors (18533738055).

55601214153 is a wasteful number, since it uses less digits than its factorization.

55601214153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18533738054.

The product of its (nonzero) digits is 18000, while the sum is 33.

The spelling of 55601214153 in words is "fifty-five billion, six hundred one million, two hundred fourteen thousand, one hundred fifty-three".

Divisors: 1 3 18533738051 55601214153