Base | Representation |
---|---|
bin | 11001010100011011000011… |
… | …01101100110011000101011 |
3 | 21022010200211210110201101021 |
4 | 30222031201231212120223 |
5 | 24244204102400323312 |
6 | 314225444304033311 |
7 | 14504360256542035 |
oct | 1452154155463053 |
9 | 238120753421337 |
10 | 55677300401707 |
11 | 16816679633056 |
12 | 62b2773302837 |
13 | 250b4681a38ba |
14 | da6b1d642c55 |
15 | 6684636b6c07 |
hex | 32a361b6662b |
55677300401707 has 32 divisors (see below), whose sum is σ = 58774670418240. Its totient is φ = 52686363924480.
The previous prime is 55677300401689. The next prime is 55677300401719. The reversal of 55677300401707 is 70710400377655.
55677300401707 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55677300401707 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55677300701707) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1266148173 + ... + 1266192145.
It is an arithmetic number, because the mean of its divisors is an integer number (1836708450570).
Almost surely, 255677300401707 is an apocalyptic number.
55677300401707 is a deficient number, since it is larger than the sum of its proper divisors (3097370016533).
55677300401707 is a wasteful number, since it uses less digits than its factorization.
55677300401707 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50703.
The product of its (nonzero) digits is 4321800, while the sum is 52.
The spelling of 55677300401707 in words is "fifty-five trillion, six hundred seventy-seven billion, three hundred million, four hundred one thousand, seven hundred seven".
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