Base | Representation |
---|---|
bin | 10000001110001000101… |
… | …10010110000000000001 |
3 | 1222021121022220011101001 |
4 | 20013010112112000001 |
5 | 33112420303112201 |
6 | 1104012445012001 |
7 | 55160346050101 |
oct | 10070426260001 |
9 | 1867538804331 |
10 | 557344972801 |
11 | 1a5406786301 |
12 | 90025854001 |
13 | 40732809646 |
14 | 1cd9322d201 |
15 | e770236301 |
hex | 81c4596001 |
557344972801 has 4 divisors (see below), whose sum is σ = 557384800000. Its totient is φ = 557305145604.
The previous prime is 557344972771. The next prime is 557344972831. The reversal of 557344972801 is 108279443755.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (557344972771) and next prime (557344972831).
It is a cyclic number.
It is not a de Polignac number, because 557344972801 - 27 = 557344972673 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (557344972831) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19892601 + ... + 19920598.
It is an arithmetic number, because the mean of its divisors is an integer number (139346200000).
Almost surely, 2557344972801 is an apocalyptic number.
It is an amenable number.
557344972801 is a deficient number, since it is larger than the sum of its proper divisors (39827199).
557344972801 is a wasteful number, since it uses less digits than its factorization.
557344972801 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39827198.
The product of its (nonzero) digits is 8467200, while the sum is 55.
The spelling of 557344972801 in words is "five hundred fifty-seven billion, three hundred forty-four million, nine hundred seventy-two thousand, eight hundred one".
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