Base | Representation |
---|---|
bin | 110011111011001100… |
… | …101000100001011001 |
3 | 12022220120222200101111 |
4 | 303323030220201121 |
5 | 1403141011003343 |
6 | 41340225420321 |
7 | 4012431120223 |
oct | 637314504131 |
9 | 168816880344 |
10 | 55754000473 |
11 | 21710752846 |
12 | a97ba9a6a1 |
13 | 5346b96c32 |
14 | 29ac9c5413 |
15 | 16b4ad8c9d |
hex | cfb328859 |
55754000473 has 2 divisors, whose sum is σ = 55754000474. Its totient is φ = 55754000472.
The previous prime is 55754000447. The next prime is 55754000483. The reversal of 55754000473 is 37400045755.
55754000473 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32316533824 + 23437466649 = 179768^2 + 153093^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-55754000473 is a prime.
It is not a weakly prime, because it can be changed into another prime (55754000413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27877000236 + 27877000237.
It is an arithmetic number, because the mean of its divisors is an integer number (27877000237).
Almost surely, 255754000473 is an apocalyptic number.
It is an amenable number.
55754000473 is a deficient number, since it is larger than the sum of its proper divisors (1).
55754000473 is an equidigital number, since it uses as much as digits as its factorization.
55754000473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 294000, while the sum is 40.
The spelling of 55754000473 in words is "fifty-five billion, seven hundred fifty-four million, four hundred seventy-three", and thus it is an aban number.
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