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5582333055011 = 40498313784117
BaseRepresentation
bin101000100111011110011…
…1110101001000000100011
3201202122222101111101110112
41101032330332221000203
51212430104230230021
615512253254521535
71114211263025666
oct121167476510043
921678871441415
105582333055011
1118624aa529879
12761a880662ab
133165477c366b
141542875396dd
159a321573d5b
hex513bcfa9023

5582333055011 has 4 divisors (see below), whose sum is σ = 5582347244112. Its totient is φ = 5582318865912.

The previous prime is 5582333054953. The next prime is 5582333055023. The reversal of 5582333055011 is 1105503332855.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5582333055011 - 222 = 5582328860707 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5582333055011.

It is not an unprimeable number, because it can be changed into a prime (5582333052011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6487076 + ... + 7297041.

It is an arithmetic number, because the mean of its divisors is an integer number (1395586811028).

Almost surely, 25582333055011 is an apocalyptic number.

5582333055011 is a deficient number, since it is larger than the sum of its proper divisors (14189101).

5582333055011 is a wasteful number, since it uses less digits than its factorization.

5582333055011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14189100.

The product of its (nonzero) digits is 270000, while the sum is 41.

Adding to 5582333055011 its reverse (1105503332855), we get a palindrome (6687836387866).

The spelling of 5582333055011 in words is "five trillion, five hundred eighty-two billion, three hundred thirty-three million, fifty-five thousand, eleven".

Divisors: 1 404983 13784117 5582333055011