Base | Representation |
---|---|
bin | 110100001000000101… |
… | …010011100000100001 |
3 | 12100110122202220100012 |
4 | 310020011103200201 |
5 | 1404111331330301 |
6 | 41413511134305 |
7 | 4020664464452 |
oct | 641005234041 |
9 | 170418686305 |
10 | 55970183201 |
11 | 21811789059 |
12 | aa20374395 |
13 | 537c8c8cca |
14 | 29cd5bb129 |
15 | 16c8a8cebb |
hex | d08153821 |
55970183201 has 2 divisors, whose sum is σ = 55970183202. Its totient is φ = 55970183200.
The previous prime is 55970183197. The next prime is 55970183219. The reversal of 55970183201 is 10238107955.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 55422576400 + 547606801 = 235420^2 + 23401^2 .
It is a cyclic number.
It is not a de Polignac number, because 55970183201 - 22 = 55970183197 is a prime.
It is a super-2 number, since 2×559701832012 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (55970183281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27985091600 + 27985091601.
It is an arithmetic number, because the mean of its divisors is an integer number (27985091601).
Almost surely, 255970183201 is an apocalyptic number.
It is an amenable number.
55970183201 is a deficient number, since it is larger than the sum of its proper divisors (1).
55970183201 is an equidigital number, since it uses as much as digits as its factorization.
55970183201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75600, while the sum is 41.
The spelling of 55970183201 in words is "fifty-five billion, nine hundred seventy million, one hundred eighty-three thousand, two hundred one".
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