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5603142544001 = 37151436284973
BaseRepresentation
bin101000110001001010101…
…0100100010101010000001
3201211122200122012221211222
41101202111110202222001
51213300213442402001
615530014222244425
71115546044540052
oct121422524425201
921748618187758
105603142544001
11187030898a962
12765b15126715
133184b2ac4262
1415529d13a729
159ab3d3dd61b
hex51895522a81

5603142544001 has 4 divisors (see below), whose sum is σ = 5754578829012. Its totient is φ = 5451706258992.

The previous prime is 5603142543989. The next prime is 5603142544003. The reversal of 5603142544001 is 1004452413065.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4996114569601 + 607027974400 = 2235199^2 + 779120^2 .

It is a cyclic number.

It is not a de Polignac number, because 5603142544001 - 214 = 5603142527617 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5603142544003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75718142450 + ... + 75718142523.

It is an arithmetic number, because the mean of its divisors is an integer number (1438644707253).

Almost surely, 25603142544001 is an apocalyptic number.

It is an amenable number.

5603142544001 is a deficient number, since it is larger than the sum of its proper divisors (151436285011).

5603142544001 is a wasteful number, since it uses less digits than its factorization.

5603142544001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 151436285010.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 5603142544001 its reverse (1004452413065), we get a palindrome (6607594957066).

The spelling of 5603142544001 in words is "five trillion, six hundred three billion, one hundred forty-two million, five hundred forty-four thousand, one".

Divisors: 1 37 151436284973 5603142544001