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56074588044113 is a prime number
BaseRepresentation
bin11001011111111111000011…
…11001101011101101010001
321100112200022110021001020102
430233333201321223231101
524322211224014402423
6315132150553022145
714545153365021002
oct1457774171535521
9240480273231212
1056074588044113
111695a1100a9001
12635776a0b4955
132539a708bc802
14dbc04b4b71a9
15673966dd8c28
hex32ffe1e6bb51

56074588044113 has 2 divisors, whose sum is σ = 56074588044114. Its totient is φ = 56074588044112.

The previous prime is 56074588044017. The next prime is 56074588044143. The reversal of 56074588044113 is 31144088547065.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 41522133150289 + 14552454893824 = 6443767^2 + 3814768^2 .

It is a cyclic number.

It is not a de Polignac number, because 56074588044113 - 28 = 56074588043857 is a prime.

It is not a weakly prime, because it can be changed into another prime (56074588044143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28037294022056 + 28037294022057.

It is an arithmetic number, because the mean of its divisors is an integer number (28037294022057).

Almost surely, 256074588044113 is an apocalyptic number.

It is an amenable number.

56074588044113 is a deficient number, since it is larger than the sum of its proper divisors (1).

56074588044113 is an equidigital number, since it uses as much as digits as its factorization.

56074588044113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12902400, while the sum is 56.

The spelling of 56074588044113 in words is "fifty-six trillion, seventy-four billion, five hundred eighty-eight million, forty-four thousand, one hundred thirteen".