Base | Representation |
---|---|
bin | 1010011100111110… |
… | …00011010001111001 |
3 | 112111002110102102101 |
4 | 11032133003101321 |
5 | 42443100330131 |
6 | 2324502503401 |
7 | 256030626661 |
oct | 51637032171 |
9 | 15432412371 |
10 | 5611730041 |
11 | 241a747925 |
12 | 1107434b61 |
13 | 6b5803628 |
14 | 3b341d1a1 |
15 | 22c9dec61 |
hex | 14e7c3479 |
5611730041 has 2 divisors, whose sum is σ = 5611730042. Its totient is φ = 5611730040.
The previous prime is 5611730029. The next prime is 5611730051. The reversal of 5611730041 is 1400371165.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3891139641 + 1720590400 = 62379^2 + 41480^2 .
It is a cyclic number.
It is not a de Polignac number, because 5611730041 - 27 = 5611729913 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5611729991 and 5611730009.
It is not a weakly prime, because it can be changed into another prime (5611730051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2805865020 + 2805865021.
It is an arithmetic number, because the mean of its divisors is an integer number (2805865021).
Almost surely, 25611730041 is an apocalyptic number.
It is an amenable number.
5611730041 is a deficient number, since it is larger than the sum of its proper divisors (1).
5611730041 is an equidigital number, since it uses as much as digits as its factorization.
5611730041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2520, while the sum is 28.
The square root of 5611730041 is about 74911.4813696806. The cubic root of 5611730041 is about 1777.0470376236.
The spelling of 5611730041 in words is "five billion, six hundred eleven million, seven hundred thirty thousand, forty-one".
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