Base | Representation |
---|---|
bin | 101000110101111010110… |
… | …0000001001100100001011 |
3 | 201212122000202002001100011 |
4 | 1101223311200021210023 |
5 | 1213432113102244113 |
6 | 15534422520452351 |
7 | 1116356643611506 |
oct | 121536540114413 |
9 | 21778022061304 |
10 | 5613346134283 |
11 | 187467460a2a8 |
12 | 767aa231a0b7 |
13 | 31944aa24c44 |
14 | 15598a33813d |
15 | 9b0390b463d |
hex | 51af580990b |
5613346134283 has 2 divisors, whose sum is σ = 5613346134284. Its totient is φ = 5613346134282.
The previous prime is 5613346134103. The next prime is 5613346134299. The reversal of 5613346134283 is 3824316433165.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5613346134283 - 229 = 5612809263371 is a prime.
It is a super-3 number, since 3×56133461342833 (a number of 39 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (5613346194283) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2806673067141 + 2806673067142.
It is an arithmetic number, because the mean of its divisors is an integer number (2806673067142).
Almost surely, 25613346134283 is an apocalyptic number.
5613346134283 is a deficient number, since it is larger than the sum of its proper divisors (1).
5613346134283 is an equidigital number, since it uses as much as digits as its factorization.
5613346134283 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3732480, while the sum is 49.
The spelling of 5613346134283 in words is "five trillion, six hundred thirteen billion, three hundred forty-six million, one hundred thirty-four thousand, two hundred eighty-three".
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