Base | Representation |
---|---|
bin | 11001100010000001010011… |
… | …01000110001011010110011 |
3 | 21100210100210111201122101221 |
4 | 30301000221220301122303 |
5 | 24324332424312003342 |
6 | 315224233213405511 |
7 | 14553210215523202 |
oct | 1461005150613263 |
9 | 240710714648357 |
10 | 56144511047347 |
11 | 16986831890288 |
12 | 6369223199897 |
13 | 25435350b8a38 |
14 | dc15a1ba9239 |
15 | 6756aa88aa67 |
hex | 331029a316b3 |
56144511047347 has 2 divisors, whose sum is σ = 56144511047348. Its totient is φ = 56144511047346.
The previous prime is 56144511047323. The next prime is 56144511047411. The reversal of 56144511047347 is 74374011544165.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-56144511047347 is a prime.
It is a super-2 number, since 2×561445110473472 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 56144511047294 and 56144511047303.
It is not a weakly prime, because it can be changed into another prime (56144511647347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28072255523673 + 28072255523674.
It is an arithmetic number, because the mean of its divisors is an integer number (28072255523674).
Almost surely, 256144511047347 is an apocalyptic number.
56144511047347 is a deficient number, since it is larger than the sum of its proper divisors (1).
56144511047347 is an equidigital number, since it uses as much as digits as its factorization.
56144511047347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5644800, while the sum is 52.
The spelling of 56144511047347 in words is "fifty-six trillion, one hundred forty-four billion, five hundred eleven million, forty-seven thousand, three hundred forty-seven".
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