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56240120753 is a prime number
BaseRepresentation
bin110100011000001011…
…000010001110110001
312101011110201011001022
4310120023002032301
51410134432331003
641500352545225
74030453065425
oct643013021661
9171143634038
1056240120753
112194009a143
12aa96852215
1353c37cc57b
142a173a6b85
1516e260e738
hexd182c23b1

56240120753 has 2 divisors, whose sum is σ = 56240120754. Its totient is φ = 56240120752.

The previous prime is 56240120737. The next prime is 56240120759. The reversal of 56240120753 is 35702104265.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51163273249 + 5076847504 = 226193^2 + 71252^2 .

It is a cyclic number.

It is not a de Polignac number, because 56240120753 - 24 = 56240120737 is a prime.

It is a super-3 number, since 3×562401207533 (a number of 33 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (56240120759) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28120060376 + 28120060377.

It is an arithmetic number, because the mean of its divisors is an integer number (28120060377).

Almost surely, 256240120753 is an apocalyptic number.

It is an amenable number.

56240120753 is a deficient number, since it is larger than the sum of its proper divisors (1).

56240120753 is an equidigital number, since it uses as much as digits as its factorization.

56240120753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50400, while the sum is 35.

The spelling of 56240120753 in words is "fifty-six billion, two hundred forty million, one hundred twenty thousand, seven hundred fifty-three".