Base | Representation |
---|---|
bin | 11001100110011000001110… |
… | …10010111110100111101011 |
3 | 21101022200022200110211221201 |
4 | 30303030013102332213223 |
5 | 24334311120220424032 |
6 | 315421120410545031 |
7 | 14600061132233236 |
oct | 1463140722764753 |
9 | 241280280424851 |
10 | 56294258764267 |
11 | 16a34296536417 |
12 | 6392255438177 |
13 | 25546ab306564 |
14 | dc8929c4841d |
15 | 6795222348e7 |
hex | 3333074be9eb |
56294258764267 has 2 divisors, whose sum is σ = 56294258764268. Its totient is φ = 56294258764266.
The previous prime is 56294258764201. The next prime is 56294258764307. The reversal of 56294258764267 is 76246785249265.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 56294258764267 - 211 = 56294258762219 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 56294258764267.
It is not a weakly prime, because it can be changed into another prime (56294258762267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28147129382133 + 28147129382134.
It is an arithmetic number, because the mean of its divisors is an integer number (28147129382134).
Almost surely, 256294258764267 is an apocalyptic number.
56294258764267 is a deficient number, since it is larger than the sum of its proper divisors (1).
56294258764267 is an equidigital number, since it uses as much as digits as its factorization.
56294258764267 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2438553600, while the sum is 73.
The spelling of 56294258764267 in words is "fifty-six trillion, two hundred ninety-four billion, two hundred fifty-eight million, seven hundred sixty-four thousand, two hundred sixty-seven".
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