Base | Representation |
---|---|
bin | 101001000000111111110… |
… | …1110010110111001110001 |
3 | 201221220102222100012001012 |
4 | 1102001333232112321301 |
5 | 1214324330311414332 |
6 | 15553355532520305 |
7 | 1121161403663255 |
oct | 122017756267161 |
9 | 21856388305035 |
10 | 5637139951217 |
11 | 18837745a7115 |
12 | 770622920095 |
13 | 31b7703b0868 |
14 | 156ba6422265 |
15 | 9b97ce293b2 |
hex | 5207fb96e71 |
5637139951217 has 2 divisors, whose sum is σ = 5637139951218. Its totient is φ = 5637139951216.
The previous prime is 5637139951199. The next prime is 5637139951259. The reversal of 5637139951217 is 7121599317365.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4167187394161 + 1469952557056 = 2041369^2 + 1212416^2 .
It is a cyclic number.
It is not a de Polignac number, because 5637139951217 - 218 = 5637139689073 is a prime.
It is a super-2 number, since 2×56371399512172 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5637139953217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2818569975608 + 2818569975609.
It is an arithmetic number, because the mean of its divisors is an integer number (2818569975609).
Almost surely, 25637139951217 is an apocalyptic number.
It is an amenable number.
5637139951217 is a deficient number, since it is larger than the sum of its proper divisors (1).
5637139951217 is an equidigital number, since it uses as much as digits as its factorization.
5637139951217 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10716300, while the sum is 59.
The spelling of 5637139951217 in words is "five trillion, six hundred thirty-seven billion, one hundred thirty-nine million, nine hundred fifty-one thousand, two hundred seventeen".
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