Base | Representation |
---|---|
bin | 101001000011110010011… |
… | …1001101111100111111011 |
3 | 201222110220121012020101010 |
4 | 1102013210321233213323 |
5 | 1214424113343332141 |
6 | 20000230315525003 |
7 | 1121463036660615 |
oct | 122074471574773 |
9 | 21873817166333 |
10 | 5643132402171 |
11 | 188626a141220 |
12 | 771815759763 |
13 | 31c1b6a35524 |
14 | 1571b4227db5 |
15 | 9bbce070416 |
hex | 521e4e6f9fb |
5643132402171 has 32 divisors (see below), whose sum is σ = 8251402680576. Its totient is φ = 3402082544000.
The previous prime is 5643132402097. The next prime is 5643132402179. The reversal of 5643132402171 is 1712042313465.
5643132402171 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 5643132402171 - 217 = 5643132271099 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5643132402179) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 35878561 + ... + 36035501.
It is an arithmetic number, because the mean of its divisors is an integer number (257856333768).
Almost surely, 25643132402171 is an apocalyptic number.
5643132402171 is a deficient number, since it is larger than the sum of its proper divisors (2608270278405).
5643132402171 is a wasteful number, since it uses less digits than its factorization.
5643132402171 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 162683.
The product of its (nonzero) digits is 120960, while the sum is 39.
The spelling of 5643132402171 in words is "five trillion, six hundred forty-three billion, one hundred thirty-two million, four hundred two thousand, one hundred seventy-one".
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