Base | Representation |
---|---|
bin | 11001101011010110111010… |
… | …11010001100010010000001 |
3 | 21101221000221122200010202112 |
4 | 30311223131122030102001 |
5 | 24400112021301012001 |
6 | 320031454214425105 |
7 | 14615326061564045 |
oct | 1465533532142201 |
9 | 241830848603675 |
10 | 56465354704001 |
11 | 16a9a905755301 |
12 | 63bb445062195 |
13 | 256787731c199 |
14 | dd2d1b284025 |
15 | 67dbd7db2cbb |
hex | 335add68c481 |
56465354704001 has 2 divisors, whose sum is σ = 56465354704002. Its totient is φ = 56465354704000.
The previous prime is 56465354703991. The next prime is 56465354704021. The reversal of 56465354704001 is 10040745356465.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 32043977347600 + 24421377356401 = 5660740^2 + 4941799^2 .
It is a cyclic number.
It is not a de Polignac number, because 56465354704001 - 214 = 56465354687617 is a prime.
It is not a weakly prime, because it can be changed into another prime (56465354704021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28232677352000 + 28232677352001.
It is an arithmetic number, because the mean of its divisors is an integer number (28232677352001).
Almost surely, 256465354704001 is an apocalyptic number.
It is an amenable number.
56465354704001 is a deficient number, since it is larger than the sum of its proper divisors (1).
56465354704001 is an equidigital number, since it uses as much as digits as its factorization.
56465354704001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048000, while the sum is 50.
The spelling of 56465354704001 in words is "fifty-six trillion, four hundred sixty-five billion, three hundred fifty-four million, seven hundred four thousand, one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •