Base | Representation |
---|---|
bin | 11001101100010111101111… |
… | …10000111100110101010001 |
3 | 21102001100210001121110001211 |
4 | 30312023313300330311101 |
5 | 24401144310043203032 |
6 | 320055451424300121 |
7 | 14621000360135302 |
oct | 1466136760746521 |
9 | 242040701543054 |
10 | 56500156616017 |
11 | 170036444a9964 |
12 | 6406138171641 |
13 | 256ac324a7c2a |
14 | dd489d3487a9 |
15 | 67ea73365747 |
hex | 3362f7c3cd51 |
56500156616017 has 2 divisors, whose sum is σ = 56500156616018. Its totient is φ = 56500156616016.
The previous prime is 56500156615993. The next prime is 56500156616087. The reversal of 56500156616017 is 71061665100565.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 56171442447121 + 328714168896 = 7494761^2 + 573336^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-56500156616017 is a prime.
It is not a weakly prime, because it can be changed into another prime (56500156616087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28250078308008 + 28250078308009.
It is an arithmetic number, because the mean of its divisors is an integer number (28250078308009).
Almost surely, 256500156616017 is an apocalyptic number.
It is an amenable number.
56500156616017 is a deficient number, since it is larger than the sum of its proper divisors (1).
56500156616017 is an equidigital number, since it uses as much as digits as its factorization.
56500156616017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134000, while the sum is 49.
The spelling of 56500156616017 in words is "fifty-six trillion, five hundred billion, one hundred fifty-six million, six hundred sixteen thousand, seventeen".
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