Base | Representation |
---|---|
bin | 11001101100011001110000… |
… | …11000101010010100011011 |
3 | 21102001110120121122001200111 |
4 | 30312030320120222110123 |
5 | 24401204020114032041 |
6 | 320100151153345151 |
7 | 14621036263233502 |
oct | 1466147030522433 |
9 | 242043517561614 |
10 | 56501240767771 |
11 | 1700405047a148 |
12 | 640639b2681b7 |
13 | 256b075c9a147 |
14 | dd496331d839 |
15 | 67ead861a981 |
hex | 33633862a51b |
56501240767771 has 2 divisors, whose sum is σ = 56501240767772. Its totient is φ = 56501240767770.
The previous prime is 56501240767757. The next prime is 56501240767999. The reversal of 56501240767771 is 17776704210565.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56501240767771 - 229 = 56500703896859 is a prime.
It is not a weakly prime, because it can be changed into another prime (56501240767171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28250620383885 + 28250620383886.
It is an arithmetic number, because the mean of its divisors is an integer number (28250620383886).
Almost surely, 256501240767771 is an apocalyptic number.
56501240767771 is a deficient number, since it is larger than the sum of its proper divisors (1).
56501240767771 is an equidigital number, since it uses as much as digits as its factorization.
56501240767771 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17287200, while the sum is 58.
The spelling of 56501240767771 in words is "fifty-six trillion, five hundred one billion, two hundred forty million, seven hundred sixty-seven thousand, seven hundred seventy-one".
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