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56510111153 is a prime number
BaseRepresentation
bin110100101000010000…
…111101110110110001
312101212021202002020202
4310220100331312301
51411213042024103
641543235444545
74040242006436
oct645020756661
9171767662222
1056510111153
1121a69536a01
12ab51156755
135437720bc2
142a411a7b8d
15170b191988
hexd2843ddb1

56510111153 has 2 divisors, whose sum is σ = 56510111154. Its totient is φ = 56510111152.

The previous prime is 56510111107. The next prime is 56510111171. The reversal of 56510111153 is 35111101565.

56510111153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 35050205089 + 21459906064 = 187217^2 + 146492^2 .

It is a cyclic number.

It is not a de Polignac number, because 56510111153 - 212 = 56510107057 is a prime.

It is a super-3 number, since 3×565101111533 (a number of 33 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (56510111173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28255055576 + 28255055577.

It is an arithmetic number, because the mean of its divisors is an integer number (28255055577).

Almost surely, 256510111153 is an apocalyptic number.

It is an amenable number.

56510111153 is a deficient number, since it is larger than the sum of its proper divisors (1).

56510111153 is an equidigital number, since it uses as much as digits as its factorization.

56510111153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2250, while the sum is 29.

The spelling of 56510111153 in words is "fifty-six billion, five hundred ten million, one hundred eleven thousand, one hundred fifty-three".