Base | Representation |
---|---|
bin | 11001101101000001111111… |
… | …10011010011111110001001 |
3 | 21102010112022220110022210212 |
4 | 30312200333303103332021 |
5 | 24402032234021443423 |
6 | 320114122332450505 |
7 | 14622432445031651 |
oct | 1466407763237611 |
9 | 242115286408725 |
10 | 56522840031113 |
11 | 17012224717405 |
12 | 640a608919a35 |
13 | 2570108ab0441 |
14 | dd5a11b87361 |
15 | 68044e98c578 |
hex | 33683fcd3f89 |
56522840031113 has 4 divisors (see below), whose sum is σ = 59497726348560. Its totient is φ = 53547953713668.
The previous prime is 56522840031089. The next prime is 56522840031127. The reversal of 56522840031113 is 31113004822565.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 56522840031113 - 226 = 56522772922249 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (56522840031173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1487443158695 + ... + 1487443158732.
It is an arithmetic number, because the mean of its divisors is an integer number (14874431587140).
Almost surely, 256522840031113 is an apocalyptic number.
It is an amenable number.
56522840031113 is a deficient number, since it is larger than the sum of its proper divisors (2974886317447).
56522840031113 is a wasteful number, since it uses less digits than its factorization.
56522840031113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2974886317446.
The product of its (nonzero) digits is 172800, while the sum is 41.
Adding to 56522840031113 its reverse (31113004822565), we get a palindrome (87635844853678).
The spelling of 56522840031113 in words is "fifty-six trillion, five hundred twenty-two billion, eight hundred forty million, thirty-one thousand, one hundred thirteen".
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