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56533277203241 is a prime number
BaseRepresentation
bin11001101101010101011011…
…11001111101101100101001
321102011112021021211121100112
430312222231321331230221
524402220122431000431
6320123010133344105
714623252211365136
oct1466525571755451
9242145237747315
1056533277203241
11170166a01862a3
126410640198035
1325710b0225837
14dd6321dc958d
15680860e02c2b
hex336aade7db29

56533277203241 has 2 divisors, whose sum is σ = 56533277203242. Its totient is φ = 56533277203240.

The previous prime is 56533277203177. The next prime is 56533277203289. The reversal of 56533277203241 is 14230277233565.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 55884535555216 + 648741648025 = 7475596^2 + 805445^2 .

It is a cyclic number.

It is not a de Polignac number, because 56533277203241 - 26 = 56533277203177 is a prime.

It is a super-2 number, since 2×565332772032412 (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 56533277203241.

It is not a weakly prime, because it can be changed into another prime (56533277203141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28266638601620 + 28266638601621.

It is an arithmetic number, because the mean of its divisors is an integer number (28266638601621).

Almost surely, 256533277203241 is an apocalyptic number.

It is an amenable number.

56533277203241 is a deficient number, since it is larger than the sum of its proper divisors (1).

56533277203241 is an equidigital number, since it uses as much as digits as its factorization.

56533277203241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6350400, while the sum is 50.

The spelling of 56533277203241 in words is "fifty-six trillion, five hundred thirty-three billion, two hundred seventy-seven million, two hundred three thousand, two hundred forty-one".