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56556740473 = 311824410983
BaseRepresentation
bin110100101011000010…
…110101111101111001
312101222112111002122121
4310223002311331321
51411312011143343
641552023121241
74041346235122
oct645302657571
9171875432577
1056556740473
1121a92895232
12ab648a3221
13544429900c
142a47465049
151710302aed
hexd2b0b5f79

56556740473 has 4 divisors (see below), whose sum is σ = 58381151488. Its totient is φ = 54732329460.

The previous prime is 56556740447. The next prime is 56556740497. The reversal of 56556740473 is 37404765565.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-56556740473 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 56556740473.

It is not an unprimeable number, because it can be changed into a prime (56556740573) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 912205461 + ... + 912205522.

It is an arithmetic number, because the mean of its divisors is an integer number (14595287872).

Almost surely, 256556740473 is an apocalyptic number.

It is an amenable number.

56556740473 is a deficient number, since it is larger than the sum of its proper divisors (1824411015).

56556740473 is a wasteful number, since it uses less digits than its factorization.

56556740473 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1824411014.

The product of its (nonzero) digits is 10584000, while the sum is 52.

The spelling of 56556740473 in words is "fifty-six billion, five hundred fifty-six million, seven hundred forty thousand, four hundred seventy-three".

Divisors: 1 31 1824410983 56556740473