Base | Representation |
---|---|
bin | 110100101011000101… |
… | …111011001110010001 |
3 | 12101222121000010222001 |
4 | 310223011323032101 |
5 | 1411312213022213 |
6 | 41552052314001 |
7 | 4041356141521 |
oct | 645305731621 |
9 | 171877003861 |
10 | 56557548433 |
11 | 21a93297271 |
12 | ab65012901 |
13 | 54444bc9b9 |
14 | 2a475d5681 |
15 | 17104121dd |
hex | d2b17b391 |
56557548433 has 4 divisors (see below), whose sum is σ = 57086123760. Its totient is φ = 56028973108.
The previous prime is 56557548431. The next prime is 56557548479. The reversal of 56557548433 is 33484575565.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 56557548433 - 21 = 56557548431 is a prime.
It is a super-2 number, since 2×565575484332 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (56557548431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 264287503 + ... + 264287716.
It is an arithmetic number, because the mean of its divisors is an integer number (14271530940).
Almost surely, 256557548433 is an apocalyptic number.
It is an amenable number.
56557548433 is a deficient number, since it is larger than the sum of its proper divisors (528575327).
56557548433 is a wasteful number, since it uses less digits than its factorization.
56557548433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 528575326.
The product of its digits is 30240000, while the sum is 55.
The spelling of 56557548433 in words is "fifty-six billion, five hundred fifty-seven million, five hundred forty-eight thousand, four hundred thirty-three".
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