Base | Representation |
---|---|
bin | 1010100101011110… |
… | …11000101000010001 |
3 | 112200001210102221021 |
4 | 11102233120220101 |
5 | 43114334330112 |
6 | 2335532555441 |
7 | 260555504614 |
oct | 52257305021 |
9 | 15601712837 |
10 | 5683120657 |
11 | 2456a78735 |
12 | 1127322b81 |
13 | 6c753b0b6 |
14 | 3bcac417b |
15 | 233de2907 |
hex | 152bd8a11 |
5683120657 has 2 divisors, whose sum is σ = 5683120658. Its totient is φ = 5683120656.
The previous prime is 5683120643. The next prime is 5683120727. The reversal of 5683120657 is 7560213865.
5683120657 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3749847696 + 1933272961 = 61236^2 + 43969^2 .
It is a cyclic number.
It is not a de Polignac number, because 5683120657 - 219 = 5682596369 is a prime.
It is a super-2 number, since 2×56831206572 = 64595720804040223298, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5683120607) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2841560328 + 2841560329.
It is an arithmetic number, because the mean of its divisors is an integer number (2841560329).
Almost surely, 25683120657 is an apocalyptic number.
It is an amenable number.
5683120657 is a deficient number, since it is larger than the sum of its proper divisors (1).
5683120657 is an equidigital number, since it uses as much as digits as its factorization.
5683120657 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 302400, while the sum is 43.
The square root of 5683120657 is about 75386.4752923228. The cubic root of 5683120657 is about 1784.5509788140.
The spelling of 5683120657 in words is "five billion, six hundred eighty-three million, one hundred twenty thousand, six hundred fifty-seven".
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