Base | Representation |
---|---|
bin | 101001010110100001000… |
… | …0100001000101010110001 |
3 | 202010022201102220121220121 |
4 | 1102231002010020222301 |
5 | 1221104000112103240 |
6 | 20030521153010241 |
7 | 1124415466611661 |
oct | 122550204105261 |
9 | 22108642817817 |
10 | 5683350112945 |
11 | 18a1327a7961a |
12 | 77957a553981 |
13 | 322c25c3351b |
14 | 15910b6a81a1 |
15 | 9cc84c0e04a |
hex | 52b42108ab1 |
5683350112945 has 16 divisors (see below), whose sum is σ = 7188630791040. Its totient is φ = 4301583801984.
The previous prime is 5683350112927. The next prime is 5683350112949. The reversal of 5683350112945 is 5492110533865.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5683350112945 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5683350112892 and 5683350112901.
It is not an unprimeable number, because it can be changed into a prime (5683350112949) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 40188324 + ... + 40329493.
It is an arithmetic number, because the mean of its divisors is an integer number (449289424440).
Almost surely, 25683350112945 is an apocalyptic number.
It is an amenable number.
5683350112945 is a deficient number, since it is larger than the sum of its proper divisors (1505280678095).
5683350112945 is a wasteful number, since it uses less digits than its factorization.
5683350112945 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80518584.
The product of its (nonzero) digits is 3888000, while the sum is 52.
The spelling of 5683350112945 in words is "five trillion, six hundred eighty-three billion, three hundred fifty million, one hundred twelve thousand, nine hundred forty-five".
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