Base | Representation |
---|---|
bin | 1010100101100010… |
… | …11001001111111001 |
3 | 112200002210012121021 |
4 | 11102301121033321 |
5 | 43120003204411 |
6 | 2335552142441 |
7 | 260563130551 |
oct | 52261311771 |
9 | 15602705537 |
10 | 5683647481 |
11 | 24572a8526 |
12 | 1127537a21 |
13 | 6c7693b25 |
14 | 3bcbc0161 |
15 | 233e98a71 |
hex | 152c593f9 |
5683647481 has 2 divisors, whose sum is σ = 5683647482. Its totient is φ = 5683647480.
The previous prime is 5683647467. The next prime is 5683647493. The reversal of 5683647481 is 1847463865.
5683647481 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4227080256 + 1456567225 = 65016^2 + 38165^2 .
It is a cyclic number.
It is not a de Polignac number, because 5683647481 - 213 = 5683639289 is a prime.
It is a super-2 number, since 2×56836474812 = 64607697376555290722, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5683647581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2841823740 + 2841823741.
It is an arithmetic number, because the mean of its divisors is an integer number (2841823741).
Almost surely, 25683647481 is an apocalyptic number.
It is an amenable number.
5683647481 is a deficient number, since it is larger than the sum of its proper divisors (1).
5683647481 is an equidigital number, since it uses as much as digits as its factorization.
5683647481 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3870720, while the sum is 52.
The square root of 5683647481 is about 75389.9693659574. The cubic root of 5683647481 is about 1784.6061196010.
The spelling of 5683647481 in words is "five billion, six hundred eighty-three million, six hundred forty-seven thousand, four hundred eighty-one".
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