Base | Representation |
---|---|
bin | 110100111101001100… |
… | …101100010000110011 |
3 | 12102202202120221022102 |
4 | 310331030230100303 |
5 | 1412422443441201 |
6 | 42042143131015 |
7 | 4052035114655 |
oct | 647514542063 |
9 | 172682527272 |
10 | 56861312051 |
11 | 22129801385 |
12 | b02a8a3a6b |
13 | 549240789b |
14 | 2a75aa86d5 |
15 | 172be1626b |
hex | d3d32c433 |
56861312051 has 2 divisors, whose sum is σ = 56861312052. Its totient is φ = 56861312050.
The previous prime is 56861312023. The next prime is 56861312087. The reversal of 56861312051 is 15021316865.
56861312051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56861312051 - 222 = 56857117747 is a prime.
It is a super-2 number, since 2×568613120512 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 56861311996 and 56861312014.
It is not a weakly prime, because it can be changed into another prime (56861312951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28430656025 + 28430656026.
It is an arithmetic number, because the mean of its divisors is an integer number (28430656026).
Almost surely, 256861312051 is an apocalyptic number.
56861312051 is a deficient number, since it is larger than the sum of its proper divisors (1).
56861312051 is an equidigital number, since it uses as much as digits as its factorization.
56861312051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 38.
The spelling of 56861312051 in words is "fifty-six billion, eight hundred sixty-one million, three hundred twelve thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.254 sec. • engine limits •