Base | Representation |
---|---|
bin | 110101000001101101… |
… | …111111011000001011 |
3 | 12102222001021220100222 |
4 | 311001231333120023 |
5 | 1413101402244323 |
6 | 42053452420255 |
7 | 4053645534521 |
oct | 650155773013 |
9 | 172861256328 |
10 | 56937149963 |
11 | 2216859a541 |
12 | b05017768b |
13 | 54a503b6a5 |
14 | 2a81baa311 |
15 | 17338e69c8 |
hex | d41b7f60b |
56937149963 has 2 divisors, whose sum is σ = 56937149964. Its totient is φ = 56937149962.
The previous prime is 56937149959. The next prime is 56937149977. The reversal of 56937149963 is 36994173965.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56937149963 - 22 = 56937149959 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 56937149896 and 56937149905.
It is not a weakly prime, because it can be changed into another prime (56937149933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28468574981 + 28468574982.
It is an arithmetic number, because the mean of its divisors is an integer number (28468574982).
Almost surely, 256937149963 is an apocalyptic number.
56937149963 is a deficient number, since it is larger than the sum of its proper divisors (1).
56937149963 is an equidigital number, since it uses as much as digits as its factorization.
56937149963 is an evil number, because the sum of its binary digits is even.
The product of its digits is 33067440, while the sum is 62.
The spelling of 56937149963 in words is "fifty-six billion, nine hundred thirty-seven million, one hundred forty-nine thousand, nine hundred sixty-three".
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