Base | Representation |
---|---|
bin | 11001111001011001110010… |
… | …11101100111110100010011 |
3 | 21110122011120112110202211020 |
4 | 30330230321131213310103 |
5 | 24431013332433203433 |
6 | 321041304222450523 |
7 | 14665231633313514 |
oct | 1474547135476423 |
9 | 243564515422736 |
10 | 56947935444243 |
11 | 17166535a24058 |
12 | 6478a84433a43 |
13 | 25a1223650a5c |
14 | 100c41ac4ca0b |
15 | 68b52e603cb3 |
hex | 33cb39767d13 |
56947935444243 has 4 divisors (see below), whose sum is σ = 75930580592328. Its totient is φ = 37965290296160.
The previous prime is 56947935444241. The next prime is 56947935444289. The reversal of 56947935444243 is 34244453974965.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 56947935444243 - 21 = 56947935444241 is a prime.
It is not an unprimeable number, because it can be changed into a prime (56947935444241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9491322574038 + ... + 9491322574043.
It is an arithmetic number, because the mean of its divisors is an integer number (18982645148082).
Almost surely, 256947935444243 is an apocalyptic number.
56947935444243 is a deficient number, since it is larger than the sum of its proper divisors (18982645148085).
56947935444243 is a wasteful number, since it uses less digits than its factorization.
56947935444243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18982645148084.
The product of its digits is 1567641600, while the sum is 69.
The spelling of 56947935444243 in words is "fifty-six trillion, nine hundred forty-seven billion, nine hundred thirty-five million, four hundred forty-four thousand, two hundred forty-three".
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