Base | Representation |
---|---|
bin | 11001111011010000001111… |
… | …00110000011000000011001 |
3 | 21110212020201002020121022220 |
4 | 30331220013212003000121 |
5 | 24433034044431121101 |
6 | 321130422055134253 |
7 | 15002642460220254 |
oct | 1475500746030031 |
9 | 243766632217286 |
10 | 57011523301401 |
11 | 171904a6686319 |
12 | 648926b974389 |
13 | 25a72184c9036 |
14 | 101153001009b |
15 | 68d001d1a636 |
hex | 33da07983019 |
57011523301401 has 4 divisors (see below), whose sum is σ = 76015364401872. Its totient is φ = 38007682200932.
The previous prime is 57011523301357. The next prime is 57011523301471. The reversal of 57011523301401 is 10410332511075.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 57011523301401 - 222 = 57011519107097 is a prime.
It is not an unprimeable number, because it can be changed into a prime (57011523301471) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9501920550231 + ... + 9501920550236.
It is an arithmetic number, because the mean of its divisors is an integer number (19003841100468).
Almost surely, 257011523301401 is an apocalyptic number.
It is an amenable number.
57011523301401 is a deficient number, since it is larger than the sum of its proper divisors (19003841100471).
57011523301401 is a wasteful number, since it uses less digits than its factorization.
57011523301401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19003841100470.
The product of its (nonzero) digits is 12600, while the sum is 33.
Adding to 57011523301401 its reverse (10410332511075), we get a palindrome (67421855812476).
The spelling of 57011523301401 in words is "fifty-seven trillion, eleven billion, five hundred twenty-three million, three hundred one thousand, four hundred one".
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