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57032036254481 is a prime number
BaseRepresentation
bin11001111011110110011100…
…10000110000001100010001
321110221012122122222120220212
430331323032100300030101
524433403102240120411
6321144053351013505
715004300011360221
oct1475731620601421
9243835578876825
1057032036254481
1117199172709602
12649123566a295
1325a91372427b2
1410125184a0081
1568d802b0c68b
hex33dece430311

57032036254481 has 2 divisors, whose sum is σ = 57032036254482. Its totient is φ = 57032036254480.

The previous prime is 57032036254463. The next prime is 57032036254517. The reversal of 57032036254481 is 18445263023075.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 47655481857025 + 9376554397456 = 6903295^2 + 3062116^2 .

It is a cyclic number.

It is not a de Polignac number, because 57032036254481 - 222 = 57032032060177 is a prime.

It is a super-2 number, since 2×570320362544812 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (57032036254421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28516018127240 + 28516018127241.

It is an arithmetic number, because the mean of its divisors is an integer number (28516018127241).

Almost surely, 257032036254481 is an apocalyptic number.

It is an amenable number.

57032036254481 is a deficient number, since it is larger than the sum of its proper divisors (1).

57032036254481 is an equidigital number, since it uses as much as digits as its factorization.

57032036254481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4838400, while the sum is 50.

The spelling of 57032036254481 in words is "fifty-seven trillion, thirty-two billion, thirty-six million, two hundred fifty-four thousand, four hundred eighty-one".