Base | Representation |
---|---|
bin | 11001111100000101100000… |
… | …10011010100010101011011 |
3 | 21110221222112021122111210111 |
4 | 30332002300103110111123 |
5 | 24434021133111414143 |
6 | 321151512045425151 |
7 | 15005004302246401 |
oct | 1476026023242533 |
9 | 243858467574714 |
10 | 57040123544923 |
11 | 171a1642787612 |
12 | 6492911b6b1b7 |
13 | 25a9b2589945c |
14 | 1012a845ab471 |
15 | 68db27aeb99d |
hex | 33e0b04d455b |
57040123544923 has 2 divisors, whose sum is σ = 57040123544924. Its totient is φ = 57040123544922.
The previous prime is 57040123544909. The next prime is 57040123544927. The reversal of 57040123544923 is 32944532104075.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 57040123544923 - 225 = 57040089990491 is a prime.
It is not a weakly prime, because it can be changed into another prime (57040123544927) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28520061772461 + 28520061772462.
It is an arithmetic number, because the mean of its divisors is an integer number (28520061772462).
Almost surely, 257040123544923 is an apocalyptic number.
57040123544923 is a deficient number, since it is larger than the sum of its proper divisors (1).
57040123544923 is an equidigital number, since it uses as much as digits as its factorization.
57040123544923 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3628800, while the sum is 49.
Adding to 57040123544923 its reverse (32944532104075), we get a palindrome (89984655648998).
The spelling of 57040123544923 in words is "fifty-seven trillion, forty billion, one hundred twenty-three million, five hundred forty-four thousand, nine hundred twenty-three".
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