Base | Representation |
---|---|
bin | 11001111100011010000011… |
… | …00010011110110101100011 |
3 | 21111000000222202011010201120 |
4 | 30332031001202132311203 |
5 | 24434211223414313021 |
6 | 321200534144103323 |
7 | 15005544453664122 |
oct | 1476150142366543 |
9 | 244000882133646 |
10 | 57051150151011 |
11 | 171a6290a37a05 |
12 | 6494a8a904b43 |
13 | 25aab9217b043 |
14 | 101340cc05ab9 |
15 | 68e070b942c6 |
hex | 33e34189ed63 |
57051150151011 has 16 divisors (see below), whose sum is σ = 80547252132384. Its totient is φ = 35794821464064.
The previous prime is 57051150150997. The next prime is 57051150151133. The reversal of 57051150151011 is 11015105115075.
It is not a de Polignac number, because 57051150151011 - 29 = 57051150150499 is a prime.
It is not an unprimeable number, because it can be changed into a prime (57051150155011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29984110 + ... + 31830003.
It is an arithmetic number, because the mean of its divisors is an integer number (5034203258274).
Almost surely, 257051150151011 is an apocalyptic number.
57051150151011 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
57051150151011 is a deficient number, since it is larger than the sum of its proper divisors (23496101981373).
57051150151011 is a wasteful number, since it uses less digits than its factorization.
57051150151011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61832230.
The product of its (nonzero) digits is 4375, while the sum is 33.
Adding to 57051150151011 its reverse (11015105115075), we get a palindrome (68066255266086).
The spelling of 57051150151011 in words is "fifty-seven trillion, fifty-one billion, one hundred fifty million, one hundred fifty-one thousand, eleven".
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