Base | Representation |
---|---|
bin | 11001111101000100101110… |
… | …10010101101001111010001 |
3 | 21111002020010122000122212201 |
4 | 30332202113102231033101 |
5 | 24440100140301132003 |
6 | 321215243552523201 |
7 | 15010315334611612 |
oct | 1476422722551721 |
9 | 244066118018781 |
10 | 57074063692753 |
11 | 17204a7a044a68 |
12 | 6499404550501 |
13 | 25b00a4358373 |
14 | 1014584029c09 |
15 | 68e9625c6b1d |
hex | 33e8974ad3d1 |
57074063692753 has 2 divisors, whose sum is σ = 57074063692754. Its totient is φ = 57074063692752.
The previous prime is 57074063692739. The next prime is 57074063692801. The reversal of 57074063692753 is 35729636047075.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 56945858877504 + 128204815249 = 7546248^2 + 358057^2 .
It is a cyclic number.
It is not a de Polignac number, because 57074063692753 - 29 = 57074063692241 is a prime.
It is not a weakly prime, because it can be changed into another prime (57074063692253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28537031846376 + 28537031846377.
It is an arithmetic number, because the mean of its divisors is an integer number (28537031846377).
Almost surely, 257074063692753 is an apocalyptic number.
It is an amenable number.
57074063692753 is a deficient number, since it is larger than the sum of its proper divisors (1).
57074063692753 is an equidigital number, since it uses as much as digits as its factorization.
57074063692753 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 200037600, while the sum is 64.
The spelling of 57074063692753 in words is "fifty-seven trillion, seventy-four billion, sixty-three million, six hundred ninety-two thousand, seven hundred fifty-three".
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