Base | Representation |
---|---|
bin | 101001100011101110011… |
… | …0000011010110001101011 |
3 | 202020000221020212011222012 |
4 | 1103013130300122301223 |
5 | 1222040043043411431 |
6 | 20051531543350135 |
7 | 1126441425166604 |
oct | 123073460326153 |
9 | 22200836764865 |
10 | 5711715216491 |
11 | 1902363376759 |
12 | 782b75a5234b |
13 | 3257c6694c6b |
14 | 15a63c936dab |
15 | 9d89504422b |
hex | 531dcc1ac6b |
5711715216491 has 2 divisors, whose sum is σ = 5711715216492. Its totient is φ = 5711715216490.
The previous prime is 5711715216469. The next prime is 5711715216503. The reversal of 5711715216491 is 1946125171175.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5711715216491 - 218 = 5711714954347 is a prime.
It is not a weakly prime, because it can be changed into another prime (5711715219491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2855857608245 + 2855857608246.
It is an arithmetic number, because the mean of its divisors is an integer number (2855857608246).
Almost surely, 25711715216491 is an apocalyptic number.
5711715216491 is a deficient number, since it is larger than the sum of its proper divisors (1).
5711715216491 is an equidigital number, since it uses as much as digits as its factorization.
5711715216491 is an evil number, because the sum of its binary digits is even.
The product of its digits is 529200, while the sum is 50.
The spelling of 5711715216491 in words is "five trillion, seven hundred eleven billion, seven hundred fifteen million, two hundred sixteen thousand, four hundred ninety-one".
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